30 g of marble stone on heating produced 11g of CO₂. The percentage of CaCO₃ in marble is

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75%

80%

83.3%

86.6%

answer is C.

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Detailed Solution

$large mathop {CaC{O_3}(S)}limits_{mathop {100g}limits_{'X';g} } ; to ;CaO(S); + ;mathop {C{O_2}(g)}limits_{mathop {44g}limits_{11g} }$

$small Weight;of;pure;CaCO3(X);required;to;produce;11;g;CO2;=;large frac{11}{44}times 100;=;25$
But 30grams of marble was required
$large %;of;CaCO_3;in;marble;=;frac{25}{30}times 100$ = 83.33%

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