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A tank full of water has a small hole at its bottom. If one fourth of the tank is emptied in t₁ seconds and the remaining three-fourths of the tank is emptied in t₂ seconds. Then the ratio (t₁/t₂) is

Moderate

A

$\sqrt{3}$

B

$\sqrt{2}$

C

$\frac{1}{\sqrt{2}}$

D

$[\frac{2}{\sqrt{3}} - 1]$

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