First slide
Collisions
Question

A ball of mass m moving with speed u undergoes a head-on elastic collision with a ball of mass nm initially at rest. The fraction of incident energy transferred to the second ball is

Moderate
Solution

As the collision is elastic, we can find

v1=m1-m2m1+m2u1 v2=2m1m1+m2u1 substitute given vallues in above equations, we get v1=1n1nu v2=2u1+n---(1) Hence the required fraction of KE transfered by m1to m2  is KE2KEInitial=12nmv2212mu2 KE2KEInitial=n(v2u)2 substitute eqn (1) KE2KEInitial=4n(1+n)2

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