MathsMaths QuestionsLinear Inequalities Questions for CBSE Class 11th

Linear Inequalities Questions for CBSE Class 11th

Solution set of x 4 ( x − 2 ) 2 > 0 is

Number of negative integral values of x satisfying 4 − x + 0.5 − 7.2 − x < 4 , x ∈ R is

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    If − 9 < x ≤ 6 then | x | ∈

    The least positive integral value of x for which 1 x − 2 + 1 x − 1 > 1 x is true is

    Solution of x − 7 x + 3 > 2 is

    The values of x which satisfy the inequalities simultaneously (i) − 3 < 2 x − 1 < 19 (ii) − 1 ≤ 2 x + 3 5 ≤ 3

    If 16 < x 2 ≤ 18 then x ∈

    Let a > 2 be a constant. If there are just 18 positive integers satisfying the inequality ( x − a ) ( x − 2 a ) x − a 2 < 0 then the value of a is

    Which of the following values of x does not satisfy 5 x + 1 ( x + 1 ) 2 < 1 ?

    Number of integers satisfying 8 + 2 x − x 2 > 6 − 3 x is

    If x ∈ [ − 4 , 6 ) then 1 x ∈

    Number of positive integers for which ( x + 3 ) ( x − 1 ) x 2 ( x − 2 ) 3 ≤ 0 h o l d s i s

    If 16 < x 2 ≤ 18 then x ∈

    The solution set of x 2 + 2 ≤ 3 x ≤ 2 x 2 − 5 is

    The number of integral values of x satisfying − x 2 + 10 x − 16 < x − 2 is

    The solution set of the inequality 2 x + 2 − 2 x + 3 − 2 x + 4 > 5 x + 1 − 5 x + 2 is

    The solution set of the inequality 4 − x + 0.5 − 7 . 2 − x − 4 < 0 , ( x ∈ R ) is

    If f ( x ) = a x 2 + b x + c and f ( − 1 ) ≥ − 4 , f ( 1 ) ≤ 0 and f ( 3 ) ≥ 5 , then the least value of a is

    Number of integers satisfying x 2 − 4 x 2 − 1 < 0 is

    Which of the following is not the solution of 16 1 / x 2 x + 3 > 1 ?

    The solution of the inequality | x + 2 | − | x | 8 − x 3 ≥ 0 is

    Number of elements in the set T = x ∣ x + 5 x − 7 − 5 = 4 x − 40 13 − x i s

    If f ( x ) = a x 2 + b x + c and f ( − 1 ) ≥ − 4 , f ( 1 ) ≤ 0 and f ( 3 ) ≥ 5 then the least value of a is

    Number of integers less than or equal to 10 satisfying the inequality 2 log 1 / 2 ⁡ ( x − 1 ) ≤ 1 3 − 1 log x 2 − x ⁡ 8 is

    Number of positive integers satisfying ( x + 2 ) x 2 − 2 x + 1 − 4 + 3 x − x 2 ≥ 0 is

    The inequality 1 2 x 6 − 2 x 4 < 2 x 2 is valid for x belongs to

    Number of integers satisfying x − 6 − 10 − x ≥ 1 is

    The number of positive integral solutions of x 2 + 9 < ( x + 3 ) 2 < 8 x + 25 is

    Consider the following two sets: A = { x : | x − 1 | < 3 } ; B = x : x 2 − 2 a x + a 2 − 4 ≤ 0 If A ∩ B = { x : − 2 < x ≤ 1 } , then the number of integers in the range of a , is

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