**Table of Contents**

- Solving Equation by Inverse Method
- Summary
- What’s Next?

In the previous segment of Class 6 Maths, we learnt about The Solution of an equation. In this segment, we will learn how to solve a linear equation using the inverse method.

## How to find the solution of an equation by inverse method?

Whenever an operation is performed on one side of an equation, the exact operation must be performed on the other side of the same equation simultaneously to keep the equation unchanged.

For example,

- Consider the equation 13x + 6 = 85.

If 10 is added to the L.H.S. of this equation, then 10 must also be added to the R.H.S. to keep the equation balanced.

That is, 13x + 6 + 10 = 85 + 10.

- Consider the equation y – 2 = 5.

If 1 is subtracted from the L.H.S. of this equation, then 1 must also be subtracted from the R.H.S. to keep the equation balanced.

That is, y – 2 – 1 = 5 – 1.

Let us understand how to find the solution of a linear equation in one variable, say 10x + 2 = 302, by the inverse method using the following steps:

**Step 1: **Identify the constant terms in the L.H.S. and the R.H.S. of the equation. Here, the constant term in L.H.S. is 2 and that in the R.H.S. is 302.

**Step 2: **Eliminate the constant terms which are placed along with the variables by adding or subtracting this constant on both sides.

Here, 2 is placed with the variable 10x. So we have to subtract 2 from both sides.

That is, 10x + 2 – 2 = 302 – 2.

∴ 10x = 300.

**Step 3: **Eliminate the coefficient of the variable by dividing both sides with the coefficient of the

variable.

So,10? = 300

10 10

∴ ? = 30

## Summary

**Solving a Linear Equation by Inverse Method**

Whenever an operation is performed on one side of an equation, the exact operation must be performed on the other side of the same equation simultaneously to keep the equation unchanged.

**What’s next?**

In our next segment of Class 6 Maths, we will understand **how to solve an equation by the transpose method.**