MathsExact Differential Equation – Definition, Theorem, Proof and Examples

Exact Differential Equation – Definition, Theorem, Proof and Examples

Exact Differential Equation – Definition

Exact Differential Equation – Definition: A differential equation is a mathematical equation that relates some function with its derivatives. In mathematics, an exact differential equation is a differential equation in which the unknown function and its derivatives appear differently on each side of the equation, but are equal throughout the equation.

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    This means that the equation is an equality between a differential form of one degree higher than the unknown function, and a differential form of the same degree. The unknown function is a function of one or more independent variables, often represented by the letters x, y, z, and t.

    Exact Differential Equation - Definition, Theorem, Proof and Examples

    Theorem

    A differential equation is a mathematical equation that relates a function with one or more of its derivatives. In particular, an exact differential equation is a differential equation in which the unknown function and its derivatives are related by an equation that is exact.

    Theorem: If a differential equation is exact, then it can be solved using the method of integration.

    This theorem is important because it provides a way to solve differential equations that would otherwise be very difficult or impossible to solve. For example, consider the differential equation

    y’ = x^2 + y^2

    This differential equation is not exact, because the left-hand side is not equal to the right-hand side derivative. However, if we take the derivative of both sides, we get

    y” = 2x + 2y y’

    which is now an exact differential equation. Therefore, we can use the theorem to solve it.

    First, we need to find the integrating factor, which is a function that when multiplied by the differential equation makes it exact. In this case, the integrating factor is

    I = e^{\int 2x\,dx} = e^{x^2}

    Now we can multiply both sides of the differential equation by the integrating factor to get

    e^{x^2}y’ = e^{x^2}\left(x^2 + y^2\right)

    Which is now an exact differential equation. Therefore, we can solve it using integration.

    \begin{align*} \int e^{x^2}y’\,dx &= \int e^{x^2}\left(x^2 + y^2\right)\,dx \\ y &= \int e^{x^2}\,dx – \int x^2e^{x^2}\,dx + C \\ &= \frac{1}{2}e^{x^2} – \frac{1}{2}\int e^{x^2}\,dx + C \\ &= \frac{1}{2}e^{x^2} – \frac{1}{2}y + C \end{align*}

    where C is an arbitrary constant. This is the general solution to the differential equation.

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