A and B can do a work in 25 days and 20 days respectively. A worked it for 10 days and then B joins with him. In how many days the work will completed.

# A and B can do a work in 25 days and 20 days respectively. A worked it for 10 days and then B joins with him. In how many days the work will completed.

1. A

$12\frac{2}{2}\text{days}$

2. B

3. C

$15\frac{2}{3}\text{days}$

4. D

$20\frac{2}{3}\text{days}$

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### Solution:

1 day work of $A=\frac{1}{25}$

1 day work of $B=\frac{1}{20}$

1 day work of A and B $=\frac{1}{25}+\frac{1}{20}$

$⇒\frac{4+5}{100}=\frac{9}{100}$

10 days work of $A=10×\frac{1}{25}=\frac{2}{5}$

Remaining work $=1-\frac{2}{5}=\frac{3}{5}$

Remaining work will be completed by A and B is

$\frac{9}{100}x=\frac{3}{5}$

x=$\frac{20}{3}$

$⇒6\frac{2}{3}$

The work will completed in 10+6

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