ArithmeticA cistern has 2 pipes. One can fill it with water in 10 hours and the other can empty it in 6 hours. In how many hours will the cistern be emptied if both the pipes are opened together when 3th4 of the cistern is already full of water ?

A cistern has 2 pipes. One can fill it with water in 10 hours and the other can empty it in 6 hours. In how many hours will the cistern be emptied if both the pipes are opened together when 3th4 of the cistern is already full of water ?

  1. A

    11 hrs 15 min

  2. B

    12 hrs 22 min

  3. C

    5 hrs 3 min

  4. D

    2 hrs 12 min

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    Solution:

    Part of  the tank filled by pipe 1 hour =110

    Part of  the tank emptied by pipe 2 in hour =16

    Cistern emptied when both are together opened  16110=10660=460=230

    230 part is emptied in 1 hour

     34th of  the tank

      302×34908=1114=11  hrs  15  minutes

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