ArithmeticA fruit-seller buys some bananas at the rate of 4 for a rupee and the same number of bananas at the rate of 5 for a rupee. He mixes the two lots and sells at 9 for two rupees. Find his gain or loss percent.

A fruit-seller buys some bananas at the rate of 4 for a rupee and the same number of bananas at the rate of 5 for a rupee. He mixes the two lots and sells at 9 for two rupees. Find his gain or loss percent.

A
1.2% gain
B
2.1% gain
C
1.2% loss
D
2.1% loss

Solution:

LCM of 4 and 5 is 20

$4 b a n a n a s \cos t i s r s . 1 \dots (1)$ $\times 5 \to 20 b a n a n a s \cos t i s r s . 5$

5 bananas cost is rs.1 $\dots (2)$ $\times 4 \to 20 b a n a n a s \cos t i s r s . 4$

by combining (1)&(2)

40 bananas cost is rs.9

sp of 9 bananas is rs. 2

LCM of 40 and 9 is 360

40 bananas cost is rs.9 $\dots (3) \times 9 \to c p o f 360 b a n a n a s i s r s 81$

given,sp of 9 bananas is rs. 2 $\dots (4) \times 40 \to s p o f 360 b a n a n a s i s r s . 80$

loss%= $\frac{1}{81} \times 100 %$

loss%=1.2%