ArithmeticA jogger running at 9 kmph along the side of running track is 250 meters ahead of the engine of a 110 meters long train running at 63 kmph in the same direction. In how much time will the train pass the jogger ?

A jogger running at 9 kmph along the side of running track is 250 meters ahead of the engine of a 110 meters long train running at 63 kmph in the same direction. In how much time will the train pass the jogger ?

A
26 sec
B
24 sec
C
22 sec
D
28 sec

Solution:

$Relative speed = S_{1} - S_{2} = (63 - 9) = 54 k m p h$

$1 k m = 1000 m, 1 h r = 3600 \sec$

$T = S \times D$

$= 54 \times \frac{1000}{3600} = 15 m / \sec$

$T i m e = \frac{360}{15} = 24 \sec$