A train 240 m long is running with a speed of 48 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

# A train 240 m long is running with a speed of 48 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

1. A

16 sec

2. B

12 sec

3. C

14 sec

4. D

17 sec

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### Solution:

Distance = 240

${S}_{1}=48\text{\hspace{0.17em}}kmph$

${S}_{2}=6\text{\hspace{0.17em}}kmph$

$\therefore \text{\hspace{0.17em}\hspace{0.17em}}Both\text{\hspace{0.17em}\hspace{0.17em}}are\text{\hspace{0.17em}\hspace{0.17em}}same\text{\hspace{0.17em}\hspace{0.17em}}direction\text{\hspace{0.17em}\hspace{0.17em}relative\hspace{0.17em}\hspace{0.17em}}speed={S}_{1}+{S}_{2}$

$=48+6=54\text{\hspace{0.17em}}kmph$

$=54×\frac{5}{18}=15\text{ \hspace{0.17em}}m/\mathrm{sec}$

$T=D/S=\frac{240}{15}=16\text{\hspace{0.17em}}\mathrm{sec}$

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