ArithmeticThe least number of 5 digits which is divided by 15, 20 and 25 leaves remainder 8 in each case.

The least number of 5 digits which is divided by 15, 20 and 25 leaves remainder 8 in each case.

  1. A

    10108

  2. B

    10208 

  3. C

    10008

  4. D

    10128

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    Solution:

    300−100⇒200+8 remainder

    1000 + 208 = 10208 is the smallest 5 digit number

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