BiologyA man having the genotype EEFfGgHH can produce p number of genetically different sperms, and a woman of genotype KkLLMmNn can generate Q number of genetically different eggs. Determine the values of P and Q.

A man having the genotype EEFfGgHH can produce p number of genetically different sperms, and a woman of genotype KkLLMmNn can generate Q number of genetically different eggs. Determine the values of P and Q.

  1. A

    P = 4, Q = 4

  2. B

    P = 4, Q = 8

  3. C

    P = 8, Q = 4

  4. D

    P = 8, Q = 8

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    Solution:

    Man having genotype  EEFfGgHH produces four types of gametes. They are EFGH, EFgH, EfgH, EfGH. Women of genotype KkLLMmNn produces 8 different types of gametes. They are KLMN, KLmn, KLMn, KLmN, kLMN, kLmn, kLMn, kLmN. Formula to know the types number of gametes that are produced with different genotypes are 2n. n = number of loci that are heterozygous.

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