Botany4.5 moles each of hydrogen and iodine heated in a sealed 10 litre vessel. At equilibrium, 3 moles of HI was found. The equilibrium constant for H2(g)  +  I2(g)  ⇌   2HI(g) is

4.5 moles each of hydrogen and iodine heated in a sealed 10 litre vessel. At equilibrium, 3 moles of HI was found. The equilibrium constant for 

H2(g)  +  I2(g)     2HI(g) is

  1. A

    1

  2. B

    10

  3. C

    5

  4. D

    0.33

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    Solution:

     

                       H2  +  I2     2HI

    Initial conc. 4.5      4.5          0

                         x         x           2x

    From question 2x = 3

    x=32=1.5

    So conc. at equilibrium 4.5 - 1.5 of  H2

    = 4.5 - 1.5 of I2 and 3 of HI

    K=HI2I2  H2= 3 × 33 ×3=1

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