BotanyA small body is projected with a velocity of 30 m/s from a point P on an inclined plane having inclination of 30o with horizontal in a direction perpendicular to the plane as shown in the figure. Then distance of the point Q from the point of projection P where the body will strike. The inclined plane is (Take g=10 m/s2)

A small body is projected with a velocity of 30 m/s from a point P on an inclined plane having inclination of 30o with horizontal in a direction perpendicular to the plane as shown in the figure. Then distance of the point Q from the point of projection P where the body will strike. The inclined plane is (Take g=10 m/s2)

  1. A

    80 m

  2. B

    120 m

  3. C

    140 m

  4. D

    60 m

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    Solution:

    Time of flight T=2ugcos30o

    T=2 x 3010 x 3/2sec=43sec

    PQ=12 x g sinα x T2=12 x 10 sin 30o x (43)2m=120 m

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