BotanyAt a certain temp. 2HI ⇋H2+ I2. Only 50% HI is dissociated as equilibrium. The equilibrium constant is

At a certain temp. $2 HI ⇋ H_{2} + I_{2} .$ Only 50% HI is dissociated as equilibrium. The equilibrium constant is

$\underset{\underset{50}{100}}{2 HI} ⇋ \underset{\underset{25}{0}}{H_{2}} + \underset{\underset{25}{0}}{I_{2}}$

$\frac{[H_{2}] [I_{2}]}{{[HI]}^{2}}$ = $\frac{25 \times 25}{50 \times 50} = 0.25$