BotanyAt constant temperature & volume, 50% of ozone is decomposed out of 2 atm of ozone taken initially and the equilibrium  is established, Kp for the decomposition of ozone is

At constant temperature & volume, 50% of ozone is decomposed out of 2 atm of ozone taken initially and the equilibrium large 2{O_{3(g)}}, rightleftharpoons ,,3{O_{2left( g right)}} is established, Kp for the decomposition of ozone is

  1. A
    {left( {frac{3}{2}} right)^3}

     

  2. B
    {left( {frac{3}{2}} right)^2}

     

  3. C
    {left( {frac{2}{3}} right)^3}

     

  4. D
    {left( {frac{2}{3}} right)^2}

     

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    Solution:

    large 2{O_3}left( g right) rightleftharpoons 3{O_2}left( g right)

    Initial pressure of O3 = 2 atm

    degree of decomposition =

    large frac{{50}}{{100}} = 0.5

    Decrease in pressure due to decomposition of O3 = 0.5 x 2

    = 1 atm

    2 moles of O3 → 3 moles of O2

    1 moles of O3 → 'x' moles of O2

    large boxed{x = 1.5}

    Number of molesα 

     

    partial pressure

    large 2{O_3}left( g right) rightleftharpoons 3{O_2}left( g right)
     
    large 2{O_3}left( g right)
    large rightleftharpoons
    large 3{O_2}left( g right)
    Initial pressure   2 atm     -
    Pressure at equilibrium   (2 - 1)   1.5
    large {K_P} = frac{{P_{{O_2}}^3}}{{P_{{O_3}}^2}}
    large {K_P} = frac{{{{left( {1.5} right)}^3}}}{{{{left( 1 right)}^2}}}
    large {K_P} = {left( {frac{3}{2}} right)^3}
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