BotanyFor the reaction 2A (g) ⇌B(g)+3C(g) at a given temperature, Kc = 16 What must be the volume of the flask, if a mixture of 2 mole each of A, B and C exist in equilibrium?

For the reaction 2A (g) $⇌ B (g) + 3 C (g)$ at a given temperature, K_c = 16 What must be the volume of the flask, if a mixture of 2 mole each of A, B and C exist in equilibrium?

A
$\frac{1}{4}$
B
$\frac{1}{2}$
C
1
D
None of these

Solution:

$K_{c} = \frac{n_{B} n_{C}^{3}}{n_{A}^{2}} \times \frac{1}{V^{2}} \Rightarrow 16 = \frac{2 \times 2^{3}}{2^{2} \times V^{2}} \Rightarrow V = \frac{1}{2}$