BotanyIn Fig., the time taken by the projectile to reach from A to B is t. Then the distance AB is equal to  

In Fig., the time taken by the projectile to reach from A to B is t. Then the distance AB is equal to
 

 

  1. A

    ut3

  2. B

    3ut m2

  3. C

    3 ut 

  4. D

    2ut

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    Solution:

    Horizontal component of velocity uH=ucos60°=u2 AC=uH×t=ut2  and   AB=ACsec30°=ut223=ut3

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