BotanyIn Haber process 30 litres of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?

In Haber process 30 litres of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?

A
20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
B
20 litres ammonia, 20 litres nitrogen, 20 litres hydrogen
C
10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
D
20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen

Solution:

$N_{2} + 3 H_{2} ⇋ 2 {NH}_{3}$

30 30 0 (Initial values)

30 - x 30 - 3x 2x (at equil.)

2x = 10; $x = \frac{10}{2} = 5$

$N_{2} = 30 - 5 = 25 L H_{2} = 30 - 3 \times 5 = 15 L$