Ka1,Ka2 and Ka3 are the respective ionisation constants for the following reactions.H2 S ⇌ H++HS-HS-⇌ H++S2-H2 S ⇌2 H++S2-The correct relationship between Ka1,Ka2,Ka3 is

# are the respective ionisation constants for the following reactions.The correct relationship between

1. A

${\mathrm{K}}_{{\mathrm{a}}_{3}}={\mathrm{K}}_{{\mathrm{a}}_{1}}×{\mathrm{K}}_{{\mathrm{a}}_{2}}$

2. B

${\mathrm{K}}_{{\mathrm{a}}_{3}}={\mathrm{K}}_{{\mathrm{a}}_{1}}+{\mathrm{K}}_{{\mathrm{a}}_{2}}$

3. C

${\mathrm{K}}_{{\mathrm{a}}_{3}}={\mathrm{K}}_{{\mathrm{a}}_{1}}-{\mathrm{K}}_{{\mathrm{a}}_{2}}$

4. D

${\mathrm{K}}_{{\mathrm{a}}_{3}}={\mathrm{K}}_{{\mathrm{a}}_{1}}/{\mathrm{K}}_{{\mathrm{a}}_{2}}$

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### Solution:

For the reaction,

For the reaction,

${\mathrm{K}}_{{\mathrm{a}}_{2}}=\frac{\left[{\mathrm{H}}^{+}\right]\left[{\mathrm{S}}^{2-}\right]}{\left[{\mathrm{HS}}^{-}\right]}$

When, the above two reactions are added, their equilibrium constants are multiplied, thus

Hence, ${\mathrm{K}}_{{\mathrm{a}}_{3}}={\mathrm{K}}_{{\mathrm{a}}_{1}}×{\mathrm{K}}_{{\mathrm{a}}_{2}}$

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