BotanyN2  +  3H2  ⇌  2NH31 mole N2 and 3 moles H2 are present at start in 1 L flask. At equilibrium NH3 formed required 100 mL of 5 M HCl for neutralisation hence KC is

N2  +  3H2    2NH3

1 mole N2 and 3 moles H2 are present at start in 1 L flask. At equilibrium NH3 formed required 100 mL of 5 M HCl for neutralisation hence KC is

  1. A

    0.520.75 2.253

  2. B

    0.520.5 2.53

  3. C

    0.5L0.75 2.53

  4. D

    None of these

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    Solution:

    NH3 formed 5 ×1001000= 0.5 mol

    N2  +  3H2    2NH3

    1 - 0.25  3 - 0.75        0.5

    KC0.520.75× 2.253

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