BotanyThe compounds A and B are mixed in equimolar proportion to form the products, . At equilibrium  13 rd of each A and B reacted. Equilibrium constant for the reaction is

The compounds A and B are mixed in equimolar proportion to form the products, 

large A, + ,B, rightleftharpoons ,C + D

. At equilibrium  13 rd of each A and B reacted. Equilibrium constant for the reaction is

  1. A

    0.5

  2. B

    4.0

  3. C

    2.5

  4. D

    0.25

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    Solution:

    large A,(g) + ,B(g), rightleftharpoons ,C(g) + D(g)

    Given initial moles of A = B

    At equilibrium 

    frac{1}{{{3^{rd}}}}{text{ each of A}}& ,B

    Δn = 0; volume of the vessel has no influence.

    Equlibrium concentration
    frac{{left( {frac{2}{3}} right)}}{V},,,,,frac{{left( {frac{2}{3}} right)}}{V},,,,,frac{{left( {frac{1}{3}} right)}}{V},,,,,frac{{left( {frac{1}{3}} right)}}{V}
    {K_C} = frac{{left[ C right]left[ D right]}}{{left[ A right]left[ D right]}} = frac{{left( {frac{1}{3}} right)left( {frac{1}{3}} right)}}{{left( {frac{2}{3}} right)left( {frac{2}{3}} right)}} = frac{1}{4} = 0.25

     

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