The equilibrium constant (K.c) for the reaction 2HCl(g)⇌H2(g)+Cl2(g) is 4×10-34 at 25°C.   What is the equilibrium constant for the reaction? 12H2(g)+12Cl2(g)⇌HCl(g)

# The equilibrium constant (K.c) for the reaction $2\mathrm{HCl}\left(\mathrm{g}\right)⇌{\mathrm{H}}_{2}\left(\mathrm{g}\right)+{\mathrm{Cl}}_{2}\left(\mathrm{g}\right)$ is   What is the equilibrium constant for the reaction? $\frac{1}{2}{\mathrm{H}}_{2}\left(\mathrm{g}\right)+\frac{1}{2}{\mathrm{Cl}}_{2}\left(\mathrm{g}\right)⇌\mathrm{HCl}\left(\mathrm{g}\right)$

1. A

$2×{10}^{-17}$

2. B

$2.5×{10}^{33}$

3. C

$5×{10}^{16}$

4. D

None of these

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### Solution:

2HCl(g)⇌H2​(g)+Cl2​(g)  Kc = 4$×$10-34

$\frac{1}{2}$H$\frac{1}{2}$Cl2$\to$HCl  ${\mathrm{K}}_{\mathrm{c}}^{1}$=$\frac{1}{\sqrt{{\mathrm{K}}_{\mathrm{c}}}}$ =$\frac{1}{\sqrt{4×{10}^{-34}}}$

${\mathrm{K}}_{\mathrm{c}}^{1}$=$\frac{1}{2×{10}^{-17}}$=

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