0.1 mole H3POx is completely neutralised by 5.6 g KOH then the true statement is:

0.1 mole H3POx is completely neutralised by 5.6 g KOH then the true statement is:

1. A

x = 3 and given acid is dibasic

2. B

x = 4 and given acid has no P-H linkage

3. C

x = 2 and given acid does not form acid salt

4. D

all of these

Fill Out the Form for Expert Academic Guidance!l

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)

Solution:

If x = 4
${\mathrm{H}}_{3}{\mathrm{PO}}_{4}+3\mathrm{KOH}⟶{\mathrm{K}}_{3}{\mathrm{PO}}_{4}+3{\mathrm{H}}_{2}\mathrm{O}$
0.1 mole → 0.3 mole
If x = 3
${\mathrm{H}}_{3}{\mathrm{PO}}_{3}+2\mathrm{KOH}⟶{\mathrm{K}}_{2}{\mathrm{HPO}}_{3}+2{\mathrm{H}}_{2}\mathrm{O}$
0.1 mole → 0.2 mole
If x=2
${\mathrm{H}}_{3}{\mathrm{PO}}_{2}+\mathrm{KOH}⟶{\mathrm{KH}}_{2}{\mathrm{PO}}_{2}+{\mathrm{H}}_{2}\mathrm{O}$
0.1 mole→0.1 mole
So, if x = 2, 5.6g KOH will be required.

Related content

 GK Questions on Global Warming What is Analog Computer? Types and How is it Different from Digital Computer? Possessive Nouns NEET Exam Centres in Arunachal Pradesh 2024 What is an Electric Circuit? How does it Work? GK Questions On Bihar: State Of India Plural Nouns NEET Exam Centres in Andhra Pradesh 2024 Maharashtra NEET UG Merit List 2023 5 Lesser Known Tips to Secure AIR 1 in NEET 2024

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)