0.1 mole H3POx is completely neutralised by 5.6 g KOH then the true statement is: - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
x = 3 and given acid is dibasic
B
x = 4 and given acid has no P-H linkage
C
x = 2 and given acid does not form acid salt
D
all of these

Solution:

If x = 4
$H_{3} {PO}_{4} + 3 KOH ⟶ K_{3} {PO}_{4} + 3 H_{2} O$
0.1 mole → 0.3 mole
If x = 3
$H_{3} {PO}_{3} + 2 KOH ⟶ K_{2} {HPO}_{3} + 2 H_{2} O$
0.1 mole → 0.2 mole
If x=2
$H_{3} {PO}_{2} + KOH ⟶ {KH}_{2} {PO}_{2} + H_{2} O$
0.1 mole→0.1 mole
So, if x = 2, 5.6g KOH will be required.

0.1 mole H₃PO_x is completely neutralised by 5.6 g KOH then the true statement is:

Solution:

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