120 g of an ideal gas of molecular weight 40 is confined to a volume of 20 litre at 400 K, then the pressure of gas is

# 120 g of an ideal gas of molecular weight 40 is confined to a volume of 20 litre at 400 K, then the pressure of gas is

1. A

490 atm

2. B

4.92 atm

3. C

2236 atm

4. D

22.4 atm

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### Solution:

$\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}}$

$\mathrm{P}=\frac{3\text{\hspace{0.17em}}×\text{\hspace{0.17em}}0.082\text{\hspace{0.17em}\hspace{0.17em}}×\text{\hspace{0.17em}}400}{20}\text{\hspace{0.17em}\hspace{0.17em}}⇒\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{P}=4.92\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{atm}$

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