120 g of an ideal gas of molecular weight 40 is confined to a volume of 20 litre at 400 K, then the pressure of gas is

120 g of an ideal gas of molecular weight 40 is confined to a volume of 20 litre at 400 K, then the pressure of gas is

  1. A

    490 atm

  2. B

    4.92 atm

  3. C

    2236 atm

  4. D

    22.4 atm

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    Solution:

    P=nRTV

    P=3×0.082  ×40020    P=4.92   atm

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