128 grams of rhombic sulphur when burnt in excess of oxygen liberated Q kJ of heat. Enthalpy of combustion of rhombic sulphur is - kJ/mole

A
$- 4 Q$
B
$- 2 Q$
C
$- \frac{Q}{2}$
D
$- \frac{Q}{4}$

Solution:

$Rhombic sulphur is S_{8} . S_{8} + 8 O_{2} \to 8 {SO}_{2}; 256 g liberates X kJ 128 g liberates Q kJ X = 2 Q kJ; One mole of rhombic sulphur weighs 256 g Heat liberated by the combustion of one mole of substance is Enthalpy of combustion . Thus, ∆^{0} H_{c} = - 2 Q kJ$

128 grams of rhombic sulphur when burnt in excess of oxygen liberated Q kJ of heat. Enthalpy of combustion of rhombic sulphur is -------------- kJ/mole

Solution:

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