128 grams of rhombic sulphur when burnt in excess of oxygen liberated Q kJ of heat. Enthalpy of combustion of rhombic sulphur is -------------- kJ/mole

  1. A

    -4Q

  2. B

    -2Q

  3. C

    -Q2

  4. D

    -Q4

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    Solution:

    Rhombic sulphur is S8. S8+8O2 8SO2; 256 g  liberates   X kJ 128 g  liberates   Q kJ X=2Q kJ; One mole of rhombic sulphur weighs 256g Heat liberated by the combustion of one mole of substance is Enthalpy of combustion. Thus,   0Hc=-2Q kJ

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