2HCl(g)→H2(g)+Cl2(g)-y kJ;From the above data, calculate the heat of formation of HCl (g) in kJ/mole.

$2 HCl (g) \to H_{2} (g) + {Cl}_{2} (g) - y kJ;$
From the above data, calculate the heat of formation of HCl (g) in kJ/mole.

A
$\frac{y}{2}$
B
$y$
C
$- \frac{y}{2}$
D
$- y$

Solution:

$2 HCl (g) \to H_{2} (g) + {Cl}_{2} (g), ∆ H = y kJ; \frac{1}{2} H_{2} (g) + \frac{1}{2} {Cl}_{2} (g) \to HCl (g), ∆ H = - \frac{y}{2} kJ;$

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