4 mole of a mixture of Mohr's salt and Fer(SO4)3 requires 500 ml of 1M K2Cr2O2 for complete oxidation in acidic medium. The mole % of the Mohr's salt in the mixture is: - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
25
B
50
C
60
D
75

Solution:

${Cr}_{2} O_{7}^{2 -} + 6 {Fe}^{2 +} (n = 1) (Mohr' s salt)$ $+ 14 H^{+} ⟶ 2 {Cr}^{3 +} + 6 {Fe}^{3 +} + 7 H_{2} O$
Equivalent of Fe²⁺ = moles of Mohrs salt
= equivalent of K₂Cr₂O₇
=500 x 10^-3 x 6 x 1 = 3.0
Hence, mole per cent of Mohr's salt
$= \frac{3}{4} \times 100 = 75$

4 mole of a mixture of Mohr's salt and Fer(SO₄)₃ requires 500 ml of 1M K₂Cr₂O₂ for complete oxidation in acidic medium. The mole % of the Mohr's salt in the mixture is:

Solution:

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