4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution?

A
0.615 mol L^-1
B
0.428 mol L^-1
C
0.99 mol L^-1
D
0.301 mol L^-1

Solution:

No. of moles of NaOH $= \frac{4 .28}{40} = 0 .107$
Volume of solution = 250 cm³
$M = \frac{n}{V (in L)} = \frac{0 .107}{250} \times 1000 = 0 .428 mol L^{- 1}$

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