50ml of a certain sample of H2O2 gives 1200ml . of O2 at S.T.P. The volume strength of H2O2 is

# ${\mathrm{H}}_{2}{\mathrm{O}}_{2}$ is

1. A

22.4V

2. B

20V

3. C

24V

4. D

11.2V

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### Solution:

$50ml\text{\hspace{0.17em}\hspace{0.17em}}of\text{\hspace{0.17em}}{H}_{2}{O}_{2}\text{\hspace{0.17em}}-----1200\text{\hspace{0.17em}}ml\text{\hspace{0.17em}}of\text{\hspace{0.17em}}{O}_{2}$

$1lit\text{\hspace{0.17em}\hspace{0.17em}}of\text{\hspace{0.17em}}{H}_{2}{O}_{2}\text{\hspace{0.17em}}-----?$

$\frac{1×1200}{50}=24lit\text{\hspace{0.17em}}of\text{\hspace{0.17em}\hspace{0.17em}}{O}_{2}$

$\therefore V.S=24V$

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