A 10 g of a gas at atmospheric pressure is cooled from 2730C  to  00C keeping the volume constant, its pressure would become

# A 10 g of a gas at atmospheric pressure is cooled from ${273}^{0}C\text{\hspace{0.17em}\hspace{0.17em}}to\text{\hspace{0.17em}\hspace{0.17em}}{0}^{0}C$ keeping the volume constant, its pressure would become

1. A

1/2 atm

2. B

1/273 atm

3. C

2 atm

4. D

273 atm

Fill Out the Form for Expert Academic Guidance!l

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)

### Solution:

$\begin{array}{l}{\mathrm{T}}_{1}\text{\hspace{0.17em}\hspace{0.17em}}={273}^{0}\mathrm{C}=273+273\mathrm{K}=546\mathrm{K}\\ {\mathrm{T}}_{2}\text{\hspace{0.17em}\hspace{0.17em}}={0}^{0}\mathrm{C}=273+{0}^{0}\mathrm{C}=273\mathrm{K}\\ {\mathrm{P}}_{1}=1;\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}{\mathrm{P}}_{2}=\text{\hspace{0.17em}}?\end{array}$

According to Gay-Lussac's law

$\frac{{\mathrm{P}}_{1}}{{\mathrm{T}}_{1}}=\frac{{\mathrm{P}}_{2}}{{\mathrm{T}}_{2}}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\therefore \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}{\mathrm{P}}_{2}\text{\hspace{0.17em}}=\frac{{\mathrm{P}}_{1}{\mathrm{T}}_{2}}{{\mathrm{T}}_{1}}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\frac{1\text{\hspace{0.17em}}×\text{\hspace{0.17em}\hspace{0.17em}}273\text{\hspace{0.17em}}\mathrm{K}}{546\text{\hspace{0.17em}}\mathrm{K}}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{atm}=\frac{1}{2}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{atm}$

## Related content

 Prepare M/20 Solution of Ferrous Ammonium Sulphate Difference Between Thermoplastic And Thermosetting Plastic Bleaching Powder pH Full Form Difference Between Metals and Nonmetals Difference Between Orbit and Orbital Difference between Homogeneous and Heterogeneous Differences & Comparisons Articles in Chemistry Magnesium oxide Formula Barium chloride formula

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)