ChemistryA 10 g of a gas at atmospheric pressure is cooled from 2730C  to  00C keeping the volume constant, its pressure would become

A 10 g of a gas at atmospheric pressure is cooled from 2730C  to  00C keeping the volume constant, its pressure would become

  1. A

    1/2 atm

  2. B

    1/273 atm 

  3. C

    2 atm

  4. D

    273 atm

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    Solution:

    T1  =2730C=273+273K=546KT2  =00C=273+00C=273KP1=1;   P2=?

    According to Gay-Lussac's law

    P1T1=P2T2      P2=P1T2T1=1×  273K546K  atm=12  atm

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