A 2.24L cylinder of oxygen at 1 atm and 273 K is found to develop a leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be ; - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
0.025
B
0.050
C
0.075
D
0.09

Solution:

$P \propto n initial no . of moles, n_{1} = \frac{PV}{RT} = 0 .1 mol$

( $∵$ 2.24L=0.1mole)
$\begin{array}{l} \frac{P_{1}}{P_{2}} = \frac{n_{1}}{n_{2}} \\ \frac{1}{0 .75} = \frac{0 .1}{n_{2}} n_{2} = 0 .075 \end{array}$
no. of moles escaped = 0.025

Solution:

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