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A body of Cu at 100C is in contact with another body of Cu at 0C.There occurs transfer of heat from a hot body to a cold body till both acquires the same temperature. If ΔhS and ΔS are the changes in entropy of hot and cold body, respectively, then

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a
ΔhS+ΔcS=0
b
ΔhS+ΔcS>0
c
ΔhS+ΔcS<0
d
ΔhS=ΔcS

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detailed solution

Correct option is B

Process is irreversible, so that,

Δtotal S=ΔhS+ΔcS>0.

Thus, option B is correct.

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