A body of Cu at 100∘C is in contact with another body of Cu at 0∘C.There occurs transfer of heat from a hot body to a cold body till both acquires the same temperature. If ΔhS∞ and ΔS∞ are the changes in entropy of hot and cold body, respectively, then

A body of Cu at 100C is in contact with another body of Cu at 0C.There occurs transfer of heat from a hot body to a cold body till both acquires the same temperature. If ΔhS and ΔS are the changes in entropy of hot and cold body, respectively, then

  1. A

    ΔhS+ΔcS=0

  2. B

    ΔhS+ΔcS>0

  3. C

    ΔhS+ΔcS<0

  4. D

    ΔhS=ΔcS

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    Solution:

    Process is irreversible, so that,

    Δtotal S=ΔhS+ΔcS>0.

    Thus, option B is correct.

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