A certain particle carries 2.5 x 10-16 C of static electric charge. Calculate the number of electrons present in it. - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

Solution:

$Charge on one particle = 1.6022 \times 10^{- 19} C Charge on N particles = 1.6022 \times 10^{- 19} \times N C Total charge = 2.5 \times 10^{- 16} C Thus, 1.6022 \times 10^{- 19} N = 2.5 \times 10^{- 16}$
$N = \frac{2 .5 \times 10^{- 16}}{1 .6022 \times 10^{- 19}} = 1560$

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