A gas absorbs 300 J of heat energy and expands by 600 cm3 against a constant pressure of 2×105Nm-2. The change in internal energy is : (1Nm=1J).

A gas absorbs 300 J of heat energy and expands by 600 $c m^{3}$ against a constant pressure of $2 \times 10^{5} {Nm}^{- 2}$ . The change in internal energy is : (1Nm=1J).

A
+420 J
B
-420 J
C
+180 J
D
-180 J

Solution:

$ΔU = q + w, q = 300 J$ , $w = - PΔV, P = 2 \times 10^{5} {Nm}^{- 2}$

$ΔV = 600 {cm}^{3} = 600 \times 10^{- 6} m^{3}$

w= $- 2 \times 10^{5} \times 600 \times 10^{- 6} = - 120 Nm = - 120 J$

$ΔU = 300 - 120 = 180 J$

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