The air is a mixture of a number of gases. The major components of air are oxygen and nitrogen with approximate proportion of 20% to 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 K, if the Henry’s law constants for oxygen and nitrogen are 330 x 10 7 mm and 6.51 x 10 7 mm respectively, calculate the composition of these gases in water.

# The air is a mixture of a number of gases. The major components of air are oxygen and nitrogen with approximate proportion of 20% to 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 K, if the Henry's law constants for oxygen and nitrogen are 330 x 107 mm and 6.51 x 107 mm respectively, calculate the composition of these gases in water.

1. A
N2=4.6×10−5; O2=9.22×10−5
2. B
N2=2.3×10−5; O2=4.8×10−5
3. C
N2=9.22×10−5;O2=4.6×10−5
4. D
N2=4.8×10−5; O2=2.3×10−5

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### Solution:

$\begin{array}{l}{\mathrm{p}}_{{\mathrm{N}}_{2}}=10×\frac{79}{100}=7.9\mathrm{atm}=7.9×760\mathrm{mm}\\ {\mathrm{x}}_{{\mathrm{O}}_{2}}=\frac{{\mathrm{p}}_{{\mathrm{O}}_{2}}}{{\mathrm{K}}_{\mathrm{H}}}=\frac{2×760\mathrm{mm}}{3.3×{10}^{7}\mathrm{mm}}=4.6×{10}^{-5}\\ {\mathrm{x}}_{{\mathrm{N}}_{2}}=\frac{{\mathrm{p}}_{{\mathrm{N}}_{2}}}{{\mathrm{K}}_{\mathrm{H}}}=\frac{7.9×760\mathrm{mm}}{6.51×{10}^{7}\mathrm{mm}}=9.22×{10}^{-5}\end{array}$

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