Among the following series of transition metal ions, the one where all metal ions have same 3d electronic configuration is:

# Among the following series of transition metal ions, the one where all metal ions have same 3d electronic configuration is:

1. A

${\mathrm{Ti}}^{2+},{\mathrm{V}}^{3+},{\mathrm{Cr}}^{4+},{\mathrm{Mn}}^{5+}$

2. B

${\mathrm{Ti}}^{3+},{\mathrm{V}}^{2+},{\mathrm{Cr}}^{3+},{\mathrm{Mn}}^{4+}$

3. C

${\mathrm{Ti}}^{+},{\mathrm{V}}^{4+},{\mathrm{Cr}}^{6+},{\mathrm{Mn}}^{7+}$

4. D

${\mathrm{Ti}}^{4+},{\mathrm{V}}^{3+},{\mathrm{Cr}}^{2+},{\mathrm{Mn}}^{3+}$

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### Solution:

Ti+2,V3+,Cr+4,Mn+5 have 3d2 configurations

Ti=[Ar]3d24s2

Ti+2=[Ar]3d2

V=[Ar]3d34s2

V+3=[Ar]3d2

Cr=[Ar]3d54s1

Cr+4=[Ar]3d2

Mn=[Ar]3d54s2

Mn+5=[Ar]3d2

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