Among the following series of transition metal ions, the one where all metal ions have same 3d electronic configuration is:

Among the following series of transition metal ions, the one where all metal ions have same 3d electronic configuration is:

  1. A

    Ti2+,V3+,Cr4+,Mn5+

  2. B

    Ti3+,V2+,Cr3+,Mn4+

  3. C

    Ti+,V4+,Cr6+,Mn7+

  4. D

    Ti4+,V3+,Cr2+,Mn3+

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    Solution:

    Ti+2,V3+,Cr+4,Mn+5 have 3d2 configurations

    Ti=[Ar]3d24s2

    Ti+2=[Ar]3d2

    V=[Ar]3d34s2

    V+3=[Ar]3d2

    Cr=[Ar]3d54s1

    Cr+4=[Ar]3d2

    Mn=[Ar]3d54s2

    Mn+5=[Ar]3d2

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