Solution:
W = PV = ngRT
C4H10(g) + 6.5 O2(g) 4CO2(g) + 5H2O(l)
ng = 4 - 7.5 = - 3.5
W = - 3.5 0.0821298 = 85.6 L atm
At 250C, 1 mole of butane is heated to form CO2 and H2O liquid. The work done for the given process is
W = PV = ngRT
C4H10(g) + 6.5 O2(g) 4CO2(g) + 5H2O(l)
ng = 4 - 7.5 = - 3.5
W = - 3.5 0.0821298 = 85.6 L atm