At 250C, 1 mole of butane is heated to form CO2 and H2O liquid. The work done for the given process is

  1. A

    75.6 L atm

  2. B

    85.6 L atm

  3. C

    50.3 L atm

  4. D

    90.6 L atm

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    Solution:

    W = PV = ngRT

    C4H10(g) + 6.5 O2(g) 4CO2(g) + 5H2O(l)

    ng = 4 - 7.5 = - 3.5

    W = - 3.5 ×0.0821×298 = 85.6 L atm

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