At 298 K, a mixture contains 100 ml of 0.01 M NH4OH and 10 ml of 0.1 M NH4Cl. pH of the mixture is (Kb of NH4OH = 10–5)

At 298 K, a mixture contains 100 ml of 0.01 M NH4OH and 10 ml of 0.1 M NH4Cl. pH of the mixture is (Kb of NH4OH = 10–5)

  1. A

    9

  2. B

    10

  3. C

    11

  4. D

    8

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    Solution:

    It is a basic buffer
    pOH=pKb+logVSNSVbNb pOH=5+log10(0.1)100(0.01)pOH=5pH=9

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