At 1000C and 1 atm, if the density of liquid water is 1.0 g/cc and that of water vapour is 0.0006 g/cc, then the volume occupied by water molecule in 1 litre of steam at that temperature is

At 1000C and 1 atm, if the density of liquid water is 1.0 g/cc and that of water vapour is 0.0006 g/cc, then the volume occupied by water molecule in 1 litre of steam at that temperature is

  1. A

    6 cc

  2. B

    60 cc

  3. C

    0.6 cc

  4. D

    0.06 cc

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    Solution:

    Mass of 1 L water vapour = V x d = 1000 x 0.0006 = 0.6 g

      volume of liquid water = 0.61=0.6 cc

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