Balance the half reaction, NO2-→ H+NO3- and calculate the product of number of electrons and H+ ions involved in the balanced half reaction

Balance the half reaction, NO2- H+NO3- and calculate the product of number of electrons and H+ ions involved in the balanced half reaction

  1. A

    2

  2. B

    4

  3. C

    6

  4. D

    8

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    Solution:

    NO2+H2ONO3NO2+H2ONO3+2H+NO2+H2ONO3+2H++2e¯Product  of number of  electrons  and  H+  ions  =2×2=4

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