Blackened oil painting can be restored into original form by the action of

A
Chlorine
B
${BaO}_{2}$
C
$H_{2} O_{2}$
D
${MnO}_{2}$

Solution:

$H_{2} O_{2}$ The key reactions are
$P b O + \underset{(black)}{H_{2} S} \to P b S + H_{2} O P b S + 4 H_{2} O_{2} \to \underset{(white)}{{P b S O}_{4} + 4 H_{2} O}$
When blackened statues are treated with $H_{2} O_{2}$ the PbS is oxidised to ${PbSO}_{4}$ which is colourless (White).

Solution:

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