Boron occurs in two varieties, namely 10B ( atomic mass: 10.01 amu) and  11B ( atomic mass: 11.01 amu ). The atomic mass of naturally occurring element is reported as 10.82 amu. The percent of  10B is 6this naturally occurring boron is

Boron occurs in two varieties, namely  10B ( atomic mass: 10.01 amu) and  11B ( atomic mass: 11.01 amu ). The atomic mass of naturally occurring element is reported as 10.82 amu. The percent of  10B is 6this naturally occurring boron is 

  1. A

    10

  2. B

    19

  3. C

    29

  4. D

    35

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    Solution:

    If x is the fraction of  10B, we have x(10.01amu)+(1x)(11.01amu)=10.82amu

    This gives x=0.19. Hence, percentage is 19%.

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