C10H22→C5H12+XIf this equation is considered an experiment of cracking, the compound in the place of X is:

# ${C}_{10}{H}_{22}\to {C}_{5}{H}_{12}+X$If this equation is considered an experiment of cracking, the compound in the place of X is:

1. A
${C}_{5}{H}_{10}$
2. B
${C}_{5}{H}_{12}$
3. C
${C}_{5}{H}_{8}$
4. D
${C}_{5}{H}_{5}$

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### Solution:

concept - Cracking is a reaction in which larger molecules of saturated hydrocarbons are broken down into smaller, more useful hydrocarbon molecules,
The given reaction is not balanced. A balanced equation is one in which the number of each type of atom is the same on both the reactant and product sides.
Now, for balancing the reaction, the number of carbon atoms present in reactants is 10. So, the number of carbon atoms should be 10 in the product. Then, carbon atoms in X are 5.
The number of hydrogen atoms present in reactants is 22. So, the number of hydrogen atoms should be 22 in the product. Then, the hydrogen atom in X is 10. Therefore, after cracking, the product should be ${C}_{5}{H}_{10}$.
Hence, the correct answer is option 1.  +91

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