Calculate number of electrons present in 9.5 g of PO43-: - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

Moles of ${PO}_{4}^{3 -} = \frac{9.5}{95} = 0.1 mole$
Number of electrons in 0.1 mol ${PO}_{4}^{3 -}$
= 50 x 0.1 x N_A = 5N_A

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