UncategorizedCalculate the equivalent weight of CaCl2 (at. wt; Ca= 40, Cl= 35.5)

Calculate the equivalent weight of CaCl2 (at. wt; Ca= 40, Cl= 35.5)

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    Solution:

    Mol. wt. of CaCl2=40+(2×35.5)

                                  =111gmol

    Total + ve charge on  Ca2+=2

        Eq. wt. of CaCl2= Mol. wt. of CaCl22=1112

                                          = 55.5 Ans.

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