Calculate the minimum and maximum number of electrons which may have magnetic quantum number, m = +1 and spin quantum number, s = -12, in chromium (Cr):

  1. A

    0, 1

  2. B

    1,2

  3. C

    4,6

  4. D

    2,3

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    Solution:

    Out of 6 electrons in 2p and 3p must have one electron with m = + 1 and s = -12 but in 3d-subshell an orbital having m = +1 may have spin quantum no.
    Therefore, minimum an maximum possible values are 2 and 3 respectively.

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