CHCl3→∆KOH:CCl2+KCl+H2O.This reaction is a case of

${CHCl}_{3} \to_{∆}^{KOH} : {CCl}_{2} + KCl + H_{2} O .$ This reaction is a case of

A
$α - elimination$
B
$β - elimination$
C
$γ - elimination$
D
None of these

Solution:

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