ChemistryDissociation constants of two acids HA and HB are respectively 4 × 10-10 and 4 × 10-5, whose pH value will be higher for a given molarity

Dissociation constants of two acids HA and HB are respectively 4 × 10-10 and 4 × 10-5, whose pH value will be higher for a given molarity

  1. A

    HA

  2. B

    HB

  3. C

    Both same

  4. D

    Can't say

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    Solution:

    HA    H++A-

    HB    H++B-

    For HA

    Ka = α2C

    α1  = Ka1C = 4 × 10-101

    α1 = 2 × 10-5  for C = 1 M

    Similarly    H+ =  = 2 × 10-5 ;  pH =-log [H+] = 4.7

    For HB:

      α2  = Ka2C = 1.8 × 10-51 for  C = 1 M

    α2 = 4.2 × 10-3    H+=Cα

                                                    = 4.2 × 10-3 

    pH =-log  4.2 × 10-3 = 2.37 ;   PH of HA>HB

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